Mixtures are made up of substances or components. If the mixture is fairly uniform in composition, properties, and its overall appearance, it is homogenous. If the component parts are clearly separated, it is heterogeneous. In order to identify the components in a mixture, methods must be used to sort out the components. However, the same methods will not work for sorting all substances. Four different processes would be employed to sort soluble and insoluble components in the following experiment. Introduction
Matter that people encounter in everyday life consists of mixtures of different substances. Mixtures are combinations of two or more substances in which each substance retains its own chemical identity and therefore the original properties are maintained. The substances making up a mixture are called its components. According to our General Chemistry book, there are two types of mixtures; homogeneous and heterogeneous. Homogeneous mixtures are those that are uniform in composition, properties, and appearance throughout. Heterogeneous mixtures do not have the same composition, properties and appearance. Mixtures are characterized by two different properties: each of the substances in the mixture retains its chemical identity and mixtures are separable into these components by physical means, from heating, freezing, drying, etc. If one of the substances in a mixture exceeds the amounts of the other substances in the mixture you call it an impure substance and the other substances in the mixture are impurities. The preparation of compounds usually involves their separation or isolation from reactants or other impurities. The separation of the components of mixtures is based upon the fact that each component has different physical properties. The components of mixtures are always pure substances, either compounds or elements and each pure substance will possess a unique set of properties. Similarly, every crystal of a pure substance melts at a specific temperature and a given pressure, and every
The Term Paper on Components of Professional Appearance
Business dress, personal grooming, body language, and attitude are components of a person’s professional appearance. These things can serve as forms of nonverbal communication and send messages to others about an individual. Before a person ever speaks a word, typically others around them can make judgments and form opinions based on the subtle messages provided by that person’s appearance. These ...
pure substance boils at a specific temperature and a given pressure. There are four different methods of separation depending upon differences in physical properties. They are decantation, filtration, extraction, sublimation. In decantation, a liquid is separated from a solid by gently pouring the liquid from the solid so the only the solid remains in the container. Filtration is the process of separating a solid from a liquid by using a porous substance (a filter).
Filtration allows the liquid but not the solid to pass through, again, leaving behind the insoluble substance. Extraction separates a substance from a mixture by choosing to dissolve that substance in a suitable solvent (usually water).
Sublimation happens when a solid passes directly to the gaseous state and back to the solid state without passing through the intermediary liquid state. Material and Methods
Evaporating Dish
Beaker
3.0 Grams of mixture (NH4Cl – ammonium chloride, NaCl – sodium chloride, SiO2 – silicon dioxide) Heat plate
Balance
Oven
Stirring rod
15 mL water x 2 = 30 mL water
1. obtain mass of evaporating dish.
2. Add 3.0 grams of mixture (NH4Cl – ammonium chloride, NaCl – sodium chloride, SiO2 – silicon dioxide) to the evaporating dish and weigh to obtain mass of evaporating dish and sample mixture. 3. Subtract mass of evaporating dish from mass of original sample to get mass of original sample. 4. Place dish with sample onto heat plate to sublime the NH4Cl. 5. Remove from heat to cool mixture then weigh again. The difference in mass of evaporating dish and sample prior to heating and after heating represents the amount of NH4Cl in the mixture. 6. Obtain mass of beaker using the balance.
The Essay on Mass Determination
Objective: The purpose of this experiment is to see the difference of precision of different balances. When doing experiments we determine the mass my measuring the sample with a balance. There are many kinds of balances that measure to different precisions. This experiment shows the different results that two balances can give. Summary of Procedures Determine the mass with the triple beam scale ...
7. Add 15 mL of H20 to the mixture in the evaporating dish and stir gently 8. Decant the liquid into the beaker making sure not to transfer any of the solid into the beaker. 9. Add another 15 mL of
H20 to the mixture in the evaporating dish and stir gently. Decant the liquid again into the beaker making sure not to transfer any of the solid into the beaker to extract NaCl. 10. Place beaker with sodium chloride solution onto heat plate and heat until water evaporates. Remove from heat and allow to cool. Weigh beaker. Difference between this weight and the weight of the empty beaker is the amount of NaCL in the mixture. 11. Take evaporating dish with SiO4 and heat until dry in oven. Once dry, remove evaporating dish from oven and allow to cool. Obtain the mass of SiO2 by weighting the evaporating dish with cooled mixture and subtracting mass of empty evaporating dish obtained earlier. 12. Find percent of NH4Cl, NaCl, and SiO2 in mixture by taking mass of each substance and dividing by the mass of the original sample.
Results: Separation of the Components of a Mixture
A. Mass of Evaporating Dish and Original Sample 41.606 g Mass of evaporating dish 38.859 g Mass of original sample 2.747 g Mass of evaporating dish after subliming NH4Cl 41.466 g Mass of NH4Cl 0.14 g Percent of NH4Cl 5.096 % % NH4Cl = 0.14 g / 2.747 g * 100% = 5.096 %
B. Mass of Evaporating Dish, Watch Glass and NaCl 106.521 g Mass of evaporating dish and beaker 105.214 g Mass of NaCl 1.307 g Percent of NaCl 45.32 % % NaCl = 1.307 g / 2.747 g * 100% = 45.32 %
C. Mass of Evaporating Dish and SiO2 40.104 g Mass of evaporating dish 38.859 g Mass of SiO2 1.245 g Percent of SiO2 45.322 % % SiO2 = 1.245 g /
2.747 g * 100% = 45.322 %
D. Mass of Original Sample 2.747 g Mass of determined (NH4Cl + NaCl + SiO2) 2.692 g Differences in these weights 0.055 g Percent recovery of matter 97.997 % % recovery of matter = 2.692g /2.747g = 97.997 %
Account for our errors about 2%
The Essay on Separation of a Mixtures Lab Report
The purpose of the experiment was to separate an initial heterogeneous mixture composed of 5.00 grams of salt, 2.00 grams of sand, 50.0 mL of water, 15.00 grams of pebbles, and 1.00 gram of iron filings, and leave as much salt as possible remaining. Using separation techniques including magnetizing, evaporation, filtration, etc. the heterogeneous mixture was thoroughly separated into 4.88 grams of ...
Discussion
The first step in the experiment required using the oven to heat the mixture, with ammonium chloride, sodium chloride, and silicon dioxide in the evaporating dish, until “white fumes were no longer form[ed],” according to the lab description. The goal was to sublimate the ammonium chloride, as it is not water soluble. It took about fifteen minutes to sublimate the NH4Cl. The dish had to cool as well when it came out of the oven. The mass of the dish contents were weighed and subtracted from the mass off the starting mass of the dish and the original mixture. The result was the loss of NH4Cl. Errors could have resulted from incorrectly weighing the original and ending samples. If ample time was not given to the sublimating process, NH4Cl may not have completely left the dish, the weight would not just include the mass of the other two substances. The next stage required careful decantation and stirring to remove only the liquid into a separate dish. The goal was to leave behind the insoluble substance, sand, and pour off the soluble NaCl. It was possible to accidentally remove particles of sand into the solution, which would influence the mass calculation of the two dishes. If stirring was not rigorous enough and water was not repeatedly added to sort out the sand from the liquid, there was a potential for sand staying behind as well. The final stage was to use the heating unit to evaporate the water from the solution to leave behind NaCl. At the same time, the heating unit was used to dry the sodium chloride in another dish. A calculation was made between the mass of the empty evaporating dish and the watch glass to reveal the mass of NaCl. Errors at this stage probably
resulted from inaccurate readings on the scale or not drying the samples completely. The final stage of the experiment was to isolate the sand and calculate its mass. By this late stage, any errors in measurement, timing and calculations would have trickled down to the final remaining substance. The percentage of accuracy of the three components in the experiment should total 99%. If the percentage was less than that, “you have been sloppy” according to the lab manual. Conclusion
In this experiment, it became apparent that what appears to be a simple mixture of elements is really more complicated. Heterogeneous mixtures may appear to be random collections of single substances, but when they are sorted into their components, the homogeneous elements can be observed. This was the case with this experiment. The original mixture had three substances: NaCl, NH4Cl, and SiO2. By using four methods, decantation, filtration, extraction, and sublimation, the separate components in the mixture could be isolated and weighed. If proper techniques in weighing, and using the four methods of sorting were observed and applied, the result would be three separated substances and calculations that matched those substances. The final calculation confirmed that our three substances, when sorted out, would all combine to weigh something close to the original mixture. The margin of error was within 2%
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Discussion and Conclusion In this lab, a submarine Adventure: Density Saves The Day; I had made many of the calculation for the best result of the lab. My calculations section contains: the volume of the unknown metals, where I figure out the volume of each metal so that I will be able to determine its density in order to find its identity; the density of unknown metals, where I figure out the ...
References
Book:
1.Ebbing, Darrel, D.; Gammon, Steven D. General Chemistry. 9th ed. Belmont, CA: Brooks/Cole Cenage Learning; 2009. 2. Beran, JA; Beran,JoAllen: Laboratory Manual for Principles of General Chemistry. 8th ed. Hoboken, NJ. Jon Wiley & Sons, Inc; 2009. 3.Katz, John C.; Treichel, Paul M.; Townsend, John. Chemistry and Chemical Reactivity. Belmont, CA: Cengage Learning, Inc.; 2009. 4.Somervill, Barbara A. Mass and Weight. Chicago, IL: Capstone Global Library, Ltd.; 2010. Electronic book:
Chem Wiki:The Dynamic Chemistry Textbook. http://chemwiki.ucdavis.edu/Analytical-chemistry-html. Accessed August 29, 2013. Website:
1.Measuring Mass-Examples. http://www.harpercollege.edu/tm-ps/chm/100/dgodambe/the disk/labtech/mass2.html. 2.Jefferson Lab. http://education.jlab.org/qa/mass-09.html.
